11101113001051 has 2 divisors, whose sum is σ = 11101113001052. Its totient is φ = 11101113001050.

The previous prime is 11101113001019. The next prime is 11101113001079. The reversal of 11101113001051 is 15010031110111.

11101113001051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11101113001051 - 2⁵ = 11101113001019 is a prime.

It is not a weakly prime, because it can be changed into another prime (11101113001151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5550556500525 + 5550556500526.

It is an arithmetic number, because the mean of its divisors is an integer number (5550556500526).

Almost surely, 2^{11101113001051} is an apocalyptic number.

11101113001051 is a deficient number, since it is larger than the sum of its proper divisors (1).

11101113001051 is an equidigital number, since it uses as much as digits as its factorization.

11101113001051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15, while the sum is 16.

Adding to 11101113001051 its reverse (15010031110111), we get a palindrome (26111144111162).

The spelling of 11101113001051 in words is "eleven trillion, one hundred one billion, one hundred thirteen million, one thousand, fifty-one".