Base | Representation |
---|---|
bin | 11001001111011100111011… |
… | …000010111000111110100010 |
3 | 112120001201222120011121000002 |
4 | 121033130323002320332202 |
5 | 104022314121120004442 |
6 | 1032034401202300002 |
7 | 32245265612225621 |
oct | 3117347302707642 |
9 | 476051876147002 |
10 | 111013010313122 |
11 | 32410398244985 |
12 | 1054b094657602 |
13 | 49c3635b0cc18 |
14 | 1d5b0b62396b8 |
15 | cc7a83266732 |
hex | 64f73b0b8fa2 |
111013010313122 has 4 divisors (see below), whose sum is σ = 166519515469686. Its totient is φ = 55506505156560.
The previous prime is 111013010313089. The next prime is 111013010313187. The reversal of 111013010313122 is 221313010310111.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 87920458781281 + 23092551531841 = 9376591^2 + 4805471^2 .
It is a junction number, because it is equal to n+sod(n) for n = 111013010313094 and 111013010313103.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27753252578279 + ... + 27753252578282.
Almost surely, 2111013010313122 is an apocalyptic number.
111013010313122 is a deficient number, since it is larger than the sum of its proper divisors (55506505156564).
111013010313122 is an equidigital number, since it uses as much as digits as its factorization.
111013010313122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55506505156563.
The product of its (nonzero) digits is 108, while the sum is 20.
Adding to 111013010313122 its reverse (221313010310111), we get a palindrome (332326020623233).
The spelling of 111013010313122 in words is "one hundred eleven trillion, thirteen billion, ten million, three hundred thirteen thousand, one hundred twenty-two".
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