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111020977553 is a prime number
BaseRepresentation
bin110011101100101011…
…1011010110110010001
3101121120020120000021112
41213121113122312101
53304332332240203
6123000300503105
711010126511253
oct1473127326621
9347506500245
10111020977553
11430a14a1712
121962484aa95
13a613ba0435
145532a31cd3
152d4ba6e6d8
hex19d95dad91

111020977553 has 2 divisors, whose sum is σ = 111020977554. Its totient is φ = 111020977552.

The previous prime is 111020977549. The next prime is 111020977589. The reversal of 111020977553 is 355779020111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 72185180929 + 38835796624 = 268673^2 + 197068^2 .

It is a cyclic number.

It is not a de Polignac number, because 111020977553 - 22 = 111020977549 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 111020977553.

It is not a weakly prime, because it can be changed into another prime (111020997553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55510488776 + 55510488777.

It is an arithmetic number, because the mean of its divisors is an integer number (55510488777).

Almost surely, 2111020977553 is an apocalyptic number.

It is an amenable number.

111020977553 is a deficient number, since it is larger than the sum of its proper divisors (1).

111020977553 is an equidigital number, since it uses as much as digits as its factorization.

111020977553 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 66150, while the sum is 41.

Adding to 111020977553 its reverse (355779020111), we get a palindrome (466799997664).

The spelling of 111020977553 in words is "one hundred eleven billion, twenty million, nine hundred seventy-seven thousand, five hundred fifty-three".