Base | Representation |
---|---|
bin | 11001001111100101010010… |
… | …111000100101100111000011 |
3 | 112120002121012002020011121012 |
4 | 121033211102320211213003 |
5 | 104022441024022401011 |
6 | 1032042445222551135 |
7 | 32246034443060006 |
oct | 3117452270454703 |
9 | 476077162204535 |
10 | 111022000200131 |
11 | 32414190859069 |
12 | 105509832984ab |
13 | 49c443945c0a7 |
14 | 1d5b6ca17b53d |
15 | cc7e0c5e6a8b |
hex | 64f952e259c3 |
111022000200131 has 2 divisors, whose sum is σ = 111022000200132. Its totient is φ = 111022000200130.
The previous prime is 111022000200043. The next prime is 111022000200253. The reversal of 111022000200131 is 131002000220111.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-111022000200131 is a prime.
It is a super-3 number, since 3×1110220002001313 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (111022000205131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55511000100065 + 55511000100066.
It is an arithmetic number, because the mean of its divisors is an integer number (55511000100066).
Almost surely, 2111022000200131 is an apocalyptic number.
111022000200131 is a deficient number, since it is larger than the sum of its proper divisors (1).
111022000200131 is an equidigital number, since it uses as much as digits as its factorization.
111022000200131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 111022000200131 its reverse (131002000220111), we get a palindrome (242024000420242).
The spelling of 111022000200131 in words is "one hundred eleven trillion, twenty-two billion, two hundred thousand, one hundred thirty-one".
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