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111022112102051 is a prime number
BaseRepresentation
bin11001001111100101011001…
…100011011101011010100011
3112120002121110212210101011202
4121033211121203131122203
5104022441241144231201
61032042504301231415
732246040302162453
oct3117453143353243
9476077425711152
10111022112102051
1132414238a39697
12105509b486256b
1349c44566ac047
141d5b6dad89d63
15cc7e1734cc6b
hex64f9598dd6a3

111022112102051 has 2 divisors, whose sum is σ = 111022112102052. Its totient is φ = 111022112102050.

The previous prime is 111022112101969. The next prime is 111022112102107. The reversal of 111022112102051 is 150201211220111.

It is a strong prime.

It is an emirp because it is prime and its reverse (150201211220111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111022112102051 - 214 = 111022112085667 is a prime.

It is a super-2 number, since 2×1110221121020512 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (111022112102651) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55511056051025 + 55511056051026.

It is an arithmetic number, because the mean of its divisors is an integer number (55511056051026).

Almost surely, 2111022112102051 is an apocalyptic number.

111022112102051 is a deficient number, since it is larger than the sum of its proper divisors (1).

111022112102051 is an equidigital number, since it uses as much as digits as its factorization.

111022112102051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 80, while the sum is 20.

Adding to 111022112102051 its reverse (150201211220111), we get a palindrome (261223323322162).

The spelling of 111022112102051 in words is "one hundred eleven trillion, twenty-two billion, one hundred twelve million, one hundred two thousand, fifty-one".