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11103010130019 = 33701003376673
BaseRepresentation
bin1010000110010001111011…
…1110011000100001100011
31110022102210212101110200010
42201210132332120201203
52423402431043130034
635340352532100003
72224110640635153
oct241443676304143
943272725343603
1011103010130019
1135a083a844275
1212b3a07764603
13627017753b02
142a55622b8763
15143c34cd93e9
hexa191ef98863

11103010130019 has 4 divisors (see below), whose sum is σ = 14804013506696. Its totient is φ = 7402006753344.

The previous prime is 11103010129993. The next prime is 11103010130029. The reversal of 11103010130019 is 91003101030111.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 11103010130019 - 212 = 11103010125923 is a prime.

It is a super-2 number, since 2×111030101300192 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11103010129977 and 11103010130004.

It is not an unprimeable number, because it can be changed into a prime (11103010130029) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1850501688334 + ... + 1850501688339.

It is an arithmetic number, because the mean of its divisors is an integer number (3701003376674).

Almost surely, 211103010130019 is an apocalyptic number.

11103010130019 is a deficient number, since it is larger than the sum of its proper divisors (3701003376677).

11103010130019 is an equidigital number, since it uses as much as digits as its factorization.

11103010130019 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3701003376676.

The product of its (nonzero) digits is 81, while the sum is 21.

The spelling of 11103010130019 in words is "eleven trillion, one hundred three billion, ten million, one hundred thirty thousand, nineteen".

Divisors: 1 3 3701003376673 11103010130019