Base | Representation |
---|---|
bin | 10000001010000011101… |
… | …101111001111001111011 |
3 | 10221010220111210201212211 |
4 | 100022003231321321323 |
5 | 121142404210130243 |
6 | 2210023042515551 |
7 | 143134360164142 |
oct | 20120355717173 |
9 | 3833814721784 |
10 | 1110311411323 |
11 | 398975933a34 |
12 | 15b229065bb7 |
13 | 8091815a5aa |
14 | 3ba4cb30759 |
15 | 1dd35d73d9d |
hex | 10283b79e7b |
1110311411323 has 2 divisors, whose sum is σ = 1110311411324. Its totient is φ = 1110311411322.
The previous prime is 1110311411311. The next prime is 1110311411383. The reversal of 1110311411323 is 3231141130111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1110311411323 - 233 = 1101721476731 is a prime.
It is a super-2 number, since 2×11103114113232 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1110311411294 and 1110311411303.
It is not a weakly prime, because it can be changed into another prime (1110311411383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555155705661 + 555155705662.
It is an arithmetic number, because the mean of its divisors is an integer number (555155705662).
Almost surely, 21110311411323 is an apocalyptic number.
1110311411323 is a deficient number, since it is larger than the sum of its proper divisors (1).
1110311411323 is an equidigital number, since it uses as much as digits as its factorization.
1110311411323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 22.
Adding to 1110311411323 its reverse (3231141130111), we get a palindrome (4341452541434).
The spelling of 1110311411323 in words is "one trillion, one hundred ten billion, three hundred eleven million, four hundred eleven thousand, three hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •