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1110312000001 = 6967159367303
BaseRepresentation
bin10000001010000011110…
…000001001101000000001
310221010220112220122101201
4100022003300021220001
5121142404333000001
62210023103301201
7143134365165331
oct20120360115001
93833815818351
101110312000001
113989761a6246
1215b2292aa801
1380918305519
143ba4cc450c1
151dd35e3d501
hex10283c09a01

1110312000001 has 4 divisors (see below), whose sum is σ = 1110471374272. Its totient is φ = 1110152625732.

The previous prime is 1110311999987. The next prime is 1110312000011. The reversal of 1110312000001 is 1000002130111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1110312000001 - 25 = 1110311999969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1110312000011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 79676685 + ... + 79690618.

It is an arithmetic number, because the mean of its divisors is an integer number (277617843568).

Almost surely, 21110312000001 is an apocalyptic number.

It is an amenable number.

1110312000001 is a deficient number, since it is larger than the sum of its proper divisors (159374271).

1110312000001 is an equidigital number, since it uses as much as digits as its factorization.

1110312000001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 159374270.

The product of its (nonzero) digits is 6, while the sum is 10.

Adding to 1110312000001 its reverse (1000002130111), we get a palindrome (2110314130112).

The spelling of 1110312000001 in words is "one trillion, one hundred ten billion, three hundred twelve million, one", and thus it is an aban number.

Divisors: 1 6967 159367303 1110312000001