Base | Representation |
---|---|
bin | 11001001111101101110111… |
… | …010000101011101110011010 |
3 | 112120010110221021002022201201 |
4 | 121033231313100223232122 |
5 | 104023113344302243002 |
6 | 1032051010155504414 |
7 | 32246511436536355 |
oct | 3117556720535632 |
9 | 476113837068651 |
10 | 111031200431002 |
11 | 3241808207a755 |
12 | 1055271045810a |
13 | 49c5274547797 |
14 | 1d5bd1ddd529c |
15 | cc829a176087 |
hex | 64fb7742bb9a |
111031200431002 has 4 divisors (see below), whose sum is σ = 166546800646506. Its totient is φ = 55515600215500.
The previous prime is 111031200430979. The next prime is 111031200431087. The reversal of 111031200431002 is 200134002130111.
111031200431002 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 86719881147201 + 24311319283801 = 9312351^2 + 4930651^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27757800107749 + ... + 27757800107752.
Almost surely, 2111031200431002 is an apocalyptic number.
111031200431002 is a deficient number, since it is larger than the sum of its proper divisors (55515600215504).
111031200431002 is an equidigital number, since it uses as much as digits as its factorization.
111031200431002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55515600215503.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 111031200431002 its reverse (200134002130111), we get a palindrome (311165202561113).
The spelling of 111031200431002 in words is "one hundred eleven trillion, thirty-one billion, two hundred million, four hundred thirty-one thousand, two".
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