Search a number
-
+
111031200431002 = 255515600215501
BaseRepresentation
bin11001001111101101110111…
…010000101011101110011010
3112120010110221021002022201201
4121033231313100223232122
5104023113344302243002
61032051010155504414
732246511436536355
oct3117556720535632
9476113837068651
10111031200431002
113241808207a755
121055271045810a
1349c5274547797
141d5bd1ddd529c
15cc829a176087
hex64fb7742bb9a

111031200431002 has 4 divisors (see below), whose sum is σ = 166546800646506. Its totient is φ = 55515600215500.

The previous prime is 111031200430979. The next prime is 111031200431087. The reversal of 111031200431002 is 200134002130111.

111031200431002 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 86719881147201 + 24311319283801 = 9312351^2 + 4930651^2 .

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27757800107749 + ... + 27757800107752.

Almost surely, 2111031200431002 is an apocalyptic number.

111031200431002 is a deficient number, since it is larger than the sum of its proper divisors (55515600215504).

111031200431002 is an equidigital number, since it uses as much as digits as its factorization.

111031200431002 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 55515600215503.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 111031200431002 its reverse (200134002130111), we get a palindrome (311165202561113).

The spelling of 111031200431002 in words is "one hundred eleven trillion, thirty-one billion, two hundred million, four hundred thirty-one thousand, two".

Divisors: 1 2 55515600215501 111031200431002