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111034284727193 is a prime number
BaseRepresentation
bin11001001111110000101111…
…000110010101101110011001
3112120010202220012201210200222
4121033300233012111232121
5104023141203342232233
61032052240215005425
732246651040610502
oct3117605706255631
9476122805653628
10111034284727193
1132419415086073
1210553231369875
1349c5646534a09
141d5c1338a1ba9
15cc83cad1b898
hex64fc2f195b99

111034284727193 has 2 divisors, whose sum is σ = 111034284727194. Its totient is φ = 111034284727192.

The previous prime is 111034284727181. The next prime is 111034284727337. The reversal of 111034284727193 is 391727482430111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 89991633177664 + 21042651549529 = 9486392^2 + 4587227^2 .

It is a cyclic number.

It is not a de Polignac number, because 111034284727193 - 224 = 111034267949977 is a prime.

It is a super-2 number, since 2×1110342847271932 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (111034284727493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55517142363596 + 55517142363597.

It is an arithmetic number, because the mean of its divisors is an integer number (55517142363597).

Almost surely, 2111034284727193 is an apocalyptic number.

It is an amenable number.

111034284727193 is a deficient number, since it is larger than the sum of its proper divisors (1).

111034284727193 is an equidigital number, since it uses as much as digits as its factorization.

111034284727193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2032128, while the sum is 53.

The spelling of 111034284727193 in words is "one hundred eleven trillion, thirty-four billion, two hundred eighty-four million, seven hundred twenty-seven thousand, one hundred ninety-three".