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11104404443513 is a prime number
BaseRepresentation
bin1010000110010111001000…
…0101010001000101111001
31110022120102001000221012122
42201211302011101011321
52423413310014143023
635341143141051025
72224160331255113
oct241456205210571
943276361027178
1011104404443513
1135a13958a9677
1212b41366b6a75
136271aa591194
142a565554a3b3
15143cb74092c8
hexa1972151179

11104404443513 has 2 divisors, whose sum is σ = 11104404443514. Its totient is φ = 11104404443512.

The previous prime is 11104404443501. The next prime is 11104404443549. The reversal of 11104404443513 is 31534440440111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10231278657769 + 873125785744 = 3198637^2 + 934412^2 .

It is a cyclic number.

It is not a de Polignac number, because 11104404443513 - 24 = 11104404443497 is a prime.

It is a super-2 number, since 2×111044044435132 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11104404443563) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5552202221756 + 5552202221757.

It is an arithmetic number, because the mean of its divisors is an integer number (5552202221757).

Almost surely, 211104404443513 is an apocalyptic number.

It is an amenable number.

11104404443513 is a deficient number, since it is larger than the sum of its proper divisors (1).

11104404443513 is an equidigital number, since it uses as much as digits as its factorization.

11104404443513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 46080, while the sum is 35.

Adding to 11104404443513 its reverse (31534440440111), we get a palindrome (42638844883624).

The spelling of 11104404443513 in words is "eleven trillion, one hundred four billion, four hundred four million, four hundred forty-three thousand, five hundred thirteen".