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11110010101153 is a prime number
BaseRepresentation
bin1010000110101100000000…
…1101001001110110100001
31110100002212201001211212021
42201223000031021312201
52424011300041214103
635343511305501441
72224446256464235
oct241530015116641
943302781054767
1011110010101153
1135a3802079187
1212b523baa1881
13627891a49872
142a5a27c285c5
15143ee45e9bbd
hexa1ac0349da1

11110010101153 has 2 divisors, whose sum is σ = 11110010101154. Its totient is φ = 11110010101152.

The previous prime is 11110010101067. The next prime is 11110010101171. The reversal of 11110010101153 is 35110101001111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6245660753424 + 4864349347729 = 2499132^2 + 2205527^2 .

It is a cyclic number.

It is not a de Polignac number, because 11110010101153 - 229 = 11109473230241 is a prime.

It is not a weakly prime, because it can be changed into another prime (11110010105153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555005050576 + 5555005050577.

It is an arithmetic number, because the mean of its divisors is an integer number (5555005050577).

Almost surely, 211110010101153 is an apocalyptic number.

It is an amenable number.

11110010101153 is a deficient number, since it is larger than the sum of its proper divisors (1).

11110010101153 is an equidigital number, since it uses as much as digits as its factorization.

11110010101153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15, while the sum is 16.

Adding to 11110010101153 its reverse (35110101001111), we get a palindrome (46220111102264).

The spelling of 11110010101153 in words is "eleven trillion, one hundred ten billion, ten million, one hundred one thousand, one hundred fifty-three".