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1111003143131 = 71477110745023
BaseRepresentation
bin10000001010101100111…
…100101001101111011011
310221012200201102100112102
4100022230330221233123
5121200313301040011
62210215433034015
7143160456621020
oct20125474515733
93835621370472
101111003143131
113991a0346312
1215b3a085590b
13809c856345b
143bab6955547
151dd7696173b
hex102acf29bdb

1111003143131 has 8 divisors (see below), whose sum is σ = 1269803956224. Its totient is φ = 952223849640.

The previous prime is 1111003143121. The next prime is 1111003143143. The reversal of 1111003143131 is 1313413001111.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1111003143131 - 214 = 1111003126747 is a prime.

It is a super-2 number, since 2×11110031431312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1111003143101) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5269115 + ... + 5475908.

It is an arithmetic number, because the mean of its divisors is an integer number (158725494528).

Almost surely, 21111003143131 is an apocalyptic number.

1111003143131 is a deficient number, since it is larger than the sum of its proper divisors (158800813093).

1111003143131 is a wasteful number, since it uses less digits than its factorization.

1111003143131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10759801.

The product of its (nonzero) digits is 108, while the sum is 20.

Adding to 1111003143131 its reverse (1313413001111), we get a palindrome (2424416144242).

The spelling of 1111003143131 in words is "one trillion, one hundred eleven billion, three million, one hundred forty-three thousand, one hundred thirty-one".

Divisors: 1 7 14771 103397 10745023 75215161 158714734733 1111003143131