111101112113 has 2 divisors, whose sum is σ = 111101112114. Its totient is φ = 111101112112.

The previous prime is 111101112077. The next prime is 111101112131. The reversal of 111101112113 is 311211101111.

Together with next prime (111101112131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 108456272929 + 2644839184 = 329327^2 + 51428^2 .

It is an emirp because it is prime and its reverse (311211101111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111101112113 - 2⁶ = 111101112049 is a prime.

It is a super-2 number, since 2×111101112113² (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (111101112413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55550556056 + 55550556057.

It is an arithmetic number, because the mean of its divisors is an integer number (55550556057).

Almost surely, 2^111101112113 is an apocalyptic number.

It is an amenable number.

111101112113 is a deficient number, since it is larger than the sum of its proper divisors (1).

111101112113 is an equidigital number, since it uses as much as digits as its factorization.

111101112113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 14.

Adding to 111101112113 its reverse (311211101111), we get a palindrome (422312213224).

The spelling of 111101112113 in words is "one hundred eleven billion, one hundred one million, one hundred twelve thousand, one hundred thirteen".