11110131300313 has 4 divisors (see below), whose sum is σ = 11110377815460. Its totient is φ = 11109884785168.

The previous prime is 11110131300197. The next prime is 11110131300319. The reversal of 11110131300313 is 31300313101111.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4642529550409 + 6467601749904 = 2154653^2 + 2543148^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11110131300313 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11110131300319) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 123189958 + ... + 123280111.

It is an arithmetic number, because the mean of its divisors is an integer number (2777594453865).

Almost surely, 2^{11110131300313} is an apocalyptic number.

It is an amenable number.

11110131300313 is a deficient number, since it is larger than the sum of its proper divisors (246515147).

11110131300313 is an equidigital number, since it uses as much as digits as its factorization.

11110131300313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 246515146.

The product of its (nonzero) digits is 81, while the sum is 19.

Adding to 11110131300313 its reverse (31300313101111), we get a palindrome (42410444401424).

The spelling of 11110131300313 in words is "eleven trillion, one hundred ten billion, one hundred thirty-one million, three hundred thousand, three hundred thirteen".