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11110213300330 = 253135839397743
BaseRepresentation
bin1010000110101100110001…
…0100010011000001101010
31110100010101212102102201201
42201223030110103001222
52424012204101102310
635343543405034414
72224454304604534
oct241531424230152
943303355372651
1011110213300330
1135a38a6846791
1212b5297b55a0a
136278c4b84071
142a5a46c00854
15144007386e3a
hexa1acc51306a

11110213300330 has 16 divisors (see below), whose sum is σ = 20643493100544. Its totient is φ = 4300727729040.

The previous prime is 11110213300289. The next prime is 11110213300339. The reversal of 11110213300330 is 3300331201111.

It is a junction number, because it is equal to n+sod(n) for n = 11110213300298 and 11110213300307.

It is not an unprimeable number, because it can be changed into a prime (11110213300339) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17919698562 + ... + 17919699181.

It is an arithmetic number, because the mean of its divisors is an integer number (1290218318784).

Almost surely, 211110213300330 is an apocalyptic number.

11110213300330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11110213300330 is a deficient number, since it is larger than the sum of its proper divisors (9533279800214).

11110213300330 is a wasteful number, since it uses less digits than its factorization.

11110213300330 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 35839397781.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 11110213300330 its reverse (3300331201111), we get a palindrome (14410544501441).

The spelling of 11110213300330 in words is "eleven trillion, one hundred ten billion, two hundred thirteen million, three hundred thousand, three hundred thirty".

Divisors: 1 2 5 10 31 62 155 310 35839397743 71678795486 179196988715 358393977430 1111021330033 2222042660066 5555106650165 11110213300330