Base | Representation |
---|---|
bin | 1010000110101100110001… |
… | …1000111100110110100011 |
3 | 1110100010101221201102010002 |
4 | 2201223030120330312203 |
5 | 2424012204404121402 |
6 | 35343543451130215 |
7 | 2224454321145224 |
oct | 241531430746643 |
9 | 43303357642102 |
10 | 11110214520227 |
11 | 35a38a74aa269 |
12 | 12b529844396b |
13 | 6278c51c03b4 |
14 | 2a5a4703b24b |
15 | 144007528602 |
hex | a1acc63cda3 |
11110214520227 has 2 divisors, whose sum is σ = 11110214520228. Its totient is φ = 11110214520226.
The previous prime is 11110214520203. The next prime is 11110214520257. The reversal of 11110214520227 is 72202541201111.
11110214520227 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11110214520227 - 212 = 11110214516131 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11110214520227.
It is not a weakly prime, because it can be changed into another prime (11110214520257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555107260113 + 5555107260114.
It is an arithmetic number, because the mean of its divisors is an integer number (5555107260114).
Almost surely, 211110214520227 is an apocalyptic number.
11110214520227 is a deficient number, since it is larger than the sum of its proper divisors (1).
11110214520227 is an equidigital number, since it uses as much as digits as its factorization.
11110214520227 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2240, while the sum is 29.
Adding to 11110214520227 its reverse (72202541201111), we get a palindrome (83312755721338).
The spelling of 11110214520227 in words is "eleven trillion, one hundred ten billion, two hundred fourteen million, five hundred twenty thousand, two hundred twenty-seven".
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