Base | Representation |
---|---|
bin | 10100101100011101… |
… | …10100010011000001 |
3 | 1001200022011212020101 |
4 | 22112032310103001 |
5 | 140223230314332 |
6 | 5034250242401 |
7 | 542216565166 |
oct | 122616642301 |
9 | 31608155211 |
10 | 11110401217 |
11 | 4791593973 |
12 | 21a0a26401 |
13 | 1080a70506 |
14 | 77580c06d |
15 | 4505eaae7 |
hex | 2963b44c1 |
11110401217 has 2 divisors, whose sum is σ = 11110401218. Its totient is φ = 11110401216.
The previous prime is 11110401191. The next prime is 11110401223. The reversal of 11110401217 is 71210401111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6806910016 + 4303491201 = 82504^2 + 65601^2 .
It is a cyclic number.
It is not a de Polignac number, because 11110401217 - 231 = 8962917569 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11110401194 and 11110401203.
It is not a weakly prime, because it can be changed into another prime (11110401227) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555200608 + 5555200609.
It is an arithmetic number, because the mean of its divisors is an integer number (5555200609).
Almost surely, 211110401217 is an apocalyptic number.
It is an amenable number.
11110401217 is a deficient number, since it is larger than the sum of its proper divisors (1).
11110401217 is an equidigital number, since it uses as much as digits as its factorization.
11110401217 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 56, while the sum is 19.
Adding to 11110401217 its reverse (71210401111), we get a palindrome (82320802328).
The spelling of 11110401217 in words is "eleven billion, one hundred ten million, four hundred one thousand, two hundred seventeen".
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