Base | Representation |
---|---|
bin | 10100101100011101… |
… | …10111010001011011 |
3 | 1001200022012110221201 |
4 | 22112032313101123 |
5 | 140223231212103 |
6 | 5034250415031 |
7 | 542216645545 |
oct | 122616672133 |
9 | 31608173851 |
10 | 11110413403 |
11 | 47915a2041 |
12 | 21a0a31477 |
13 | 1080a75c1b |
14 | 775812695 |
15 | 4505ee51d |
hex | 2963b745b |
11110413403 has 4 divisors (see below), whose sum is σ = 11112703888. Its totient is φ = 11108122920.
The previous prime is 11110413389. The next prime is 11110413407. The reversal of 11110413403 is 30431401111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11110413403 - 217 = 11110282331 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11110413407) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1137951 + ... + 1147672.
It is an arithmetic number, because the mean of its divisors is an integer number (2778175972).
Almost surely, 211110413403 is an apocalyptic number.
11110413403 is a deficient number, since it is larger than the sum of its proper divisors (2290485).
11110413403 is an equidigital number, since it uses as much as digits as its factorization.
11110413403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2290484.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 11110413403 its reverse (30431401111), we get a palindrome (41541814514).
The spelling of 11110413403 in words is "eleven billion, one hundred ten million, four hundred thirteen thousand, four hundred three".
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