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111110101011113 is a prime number
BaseRepresentation
bin11001010000110111010110…
…000110100000101010101001
3112120102000120222110002011112
4121100313112012200222221
5104030411441324323423
61032151135321040105
732255303611442231
oct3120672606405251
9476360528402145
10111110101011113
1132448590428356
1210565a70026035
1349cc839972989
141d61a86b42cc1
15cca366d75a78
hex650dd61a0aa9

111110101011113 has 2 divisors, whose sum is σ = 111110101011114. Its totient is φ = 111110101011112.

The previous prime is 111110101011109. The next prime is 111110101011121. The reversal of 111110101011113 is 311110101011111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 63792376662169 + 47317724348944 = 7987013^2 + 6878788^2 .

It is a cyclic number.

It is not a de Polignac number, because 111110101011113 - 22 = 111110101011109 is a prime.

It is not a weakly prime, because it can be changed into another prime (111110901011113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55555050505556 + 55555050505557.

It is an arithmetic number, because the mean of its divisors is an integer number (55555050505557).

Almost surely, 2111110101011113 is an apocalyptic number.

It is an amenable number.

111110101011113 is a deficient number, since it is larger than the sum of its proper divisors (1).

111110101011113 is an equidigital number, since it uses as much as digits as its factorization.

111110101011113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3, while the sum is 14.

Adding to 111110101011113 its reverse (311110101011111), we get a palindrome (422220202022224).

The spelling of 111110101011113 in words is "one hundred eleven trillion, one hundred ten billion, one hundred one million, eleven thousand, one hundred thirteen".