Base | Representation |
---|---|
bin | 1010000110110000000011… |
… | …0100110110010101100011 |
3 | 1110100012200021002020211221 |
4 | 2201230000310312111203 |
5 | 2424021010111430203 |
6 | 35344211034515511 |
7 | 2224515162544453 |
oct | 241540064662543 |
9 | 43305607066757 |
10 | 11111094248803 |
11 | 35a420904637a |
12 | 12b54a2b95b97 |
13 | 627a05539c53 |
14 | 2a5acbbdbd63 |
15 | 14405989dabd |
hex | a1b00d36563 |
11111094248803 has 2 divisors, whose sum is σ = 11111094248804. Its totient is φ = 11111094248802.
The previous prime is 11111094248773. The next prime is 11111094248887. The reversal of 11111094248803 is 30884249011111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11111094248803 - 29 = 11111094248291 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11111094248803.
It is not a weakly prime, because it can be changed into another prime (11111094242803) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555547124401 + 5555547124402.
It is an arithmetic number, because the mean of its divisors is an integer number (5555547124402).
Almost surely, 211111094248803 is an apocalyptic number.
11111094248803 is a deficient number, since it is larger than the sum of its proper divisors (1).
11111094248803 is an equidigital number, since it uses as much as digits as its factorization.
11111094248803 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 55296, while the sum is 43.
The spelling of 11111094248803 in words is "eleven trillion, one hundred eleven billion, ninety-four million, two hundred forty-eight thousand, eight hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.063 sec. • engine limits •