Base | Representation |
---|---|
bin | 10000001010110011010… |
… | …100010100100100001011 |
3 | 10221012222011111210220002 |
4 | 100022303110110210023 |
5 | 121201023130324042 |
6 | 2210234211353215 |
7 | 143163225156413 |
oct | 20126324244413 |
9 | 3835864453802 |
10 | 1111110011147 |
11 | 3992456a8894 |
12 | 15b4105b280b |
13 | 80a14740076 |
14 | 3bac6c13643 |
15 | 1dd81021132 |
hex | 102b351490b |
1111110011147 has 2 divisors, whose sum is σ = 1111110011148. Its totient is φ = 1111110011146.
The previous prime is 1111110011069. The next prime is 1111110011159. The reversal of 1111110011147 is 7411100111111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1111110011147 - 220 = 1111108962571 is a prime.
It is not a weakly prime, because it can be changed into another prime (1111110011047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555555005573 + 555555005574.
It is an arithmetic number, because the mean of its divisors is an integer number (555555005574).
Almost surely, 21111110011147 is an apocalyptic number.
1111110011147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1111110011147 is an equidigital number, since it uses as much as digits as its factorization.
1111110011147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28, while the sum is 20.
Adding to 1111110011147 its reverse (7411100111111), we get a palindrome (8522210122258).
The spelling of 1111110011147 in words is "one trillion, one hundred eleven billion, one hundred ten million, eleven thousand, one hundred forty-seven".
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