Base | Representation |
---|---|
bin | 1010000110110000000100… |
… | …1110101001000001001001 |
3 | 1110100012200201210202110101 |
4 | 2201230001032221001021 |
5 | 2424021013324304433 |
6 | 35344211435445401 |
7 | 2224515304164415 |
oct | 241540116510111 |
9 | 43305621722411 |
10 | 11111101009993 |
11 | 35a4211944136 |
12 | 12b54a52b6861 |
13 | 627a06a6655a |
14 | 2a5acca7bd45 |
15 | 14405a28707d |
hex | a1b013a9049 |
11111101009993 has 2 divisors, whose sum is σ = 11111101009994. Its totient is φ = 11111101009992.
The previous prime is 11111101009979. The next prime is 11111101010081. The reversal of 11111101009993 is 39990010111111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6764176244809 + 4346924765184 = 2600803^2 + 2084928^2 .
It is a cyclic number.
It is not a de Polignac number, because 11111101009993 - 221 = 11111098912841 is a prime.
It is not a weakly prime, because it can be changed into another prime (11111101009193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555550504996 + 5555550504997.
It is an arithmetic number, because the mean of its divisors is an integer number (5555550504997).
Almost surely, 211111101009993 is an apocalyptic number.
It is an amenable number.
11111101009993 is a deficient number, since it is larger than the sum of its proper divisors (1).
11111101009993 is an equidigital number, since it uses as much as digits as its factorization.
11111101009993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2187, while the sum is 37.
The spelling of 11111101009993 in words is "eleven trillion, one hundred eleven billion, one hundred one million, nine thousand, nine hundred ninety-three".
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