1111110101083 has 2 divisors, whose sum is σ = 1111110101084. Its totient is φ = 1111110101082.

The previous prime is 1111110101071. The next prime is 1111110101119. The reversal of 1111110101083 is 3801010111111.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1111110101083 - 2⁵ = 1111110101051 is a prime.

It is a super-3 number, since 3×1111110101083³ (a number of 37 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1111110101083.

It is not a weakly prime, because it can be changed into another prime (1111110108083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555555050541 + 555555050542.

It is an arithmetic number, because the mean of its divisors is an integer number (555555050542).

Almost surely, 2^{1111110101083} is an apocalyptic number.

1111110101083 is a deficient number, since it is larger than the sum of its proper divisors (1).

1111110101083 is an equidigital number, since it uses as much as digits as its factorization.

1111110101083 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 19.

Adding to 1111110101083 its reverse (3801010111111), we get a palindrome (4912120212194).

The spelling of 1111110101083 in words is "one trillion, one hundred eleven billion, one hundred ten million, one hundred one thousand, eighty-three".