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111111012099953 is a prime number
BaseRepresentation
bin11001010000111000001100…
…011010000010011101110001
3112120102002221110211012002122
4121100320030122002131301
5104030420323044144303
61032151405544524025
732255335313534015
oct3120701432023561
9476362843735078
10111111012099953
1132448a08743938
1210566085180615
1349cc95364c6b8
141d61b31b48545
15cca3bbd42e38
hex650e0c682771

111111012099953 has 2 divisors, whose sum is σ = 111111012099954. Its totient is φ = 111111012099952.

The previous prime is 111111012099911. The next prime is 111111012100013. The reversal of 111111012099953 is 359990210111111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 65102031627889 + 46008980472064 = 8068583^2 + 6782992^2 .

It is an emirp because it is prime and its reverse (359990210111111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111111012099953 - 212 = 111111012095857 is a prime.

It is not a weakly prime, because it can be changed into another prime (111111012099053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55555506049976 + 55555506049977.

It is an arithmetic number, because the mean of its divisors is an integer number (55555506049977).

Almost surely, 2111111012099953 is an apocalyptic number.

It is an amenable number.

111111012099953 is a deficient number, since it is larger than the sum of its proper divisors (1).

111111012099953 is an equidigital number, since it uses as much as digits as its factorization.

111111012099953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21870, while the sum is 44.

The spelling of 111111012099953 in words is "one hundred eleven trillion, one hundred eleven billion, twelve million, ninety-nine thousand, nine hundred fifty-three".