Base | Representation |
---|---|
bin | 11001010000111000001100… |
… | …011010000010011101110001 |
3 | 112120102002221110211012002122 |
4 | 121100320030122002131301 |
5 | 104030420323044144303 |
6 | 1032151405544524025 |
7 | 32255335313534015 |
oct | 3120701432023561 |
9 | 476362843735078 |
10 | 111111012099953 |
11 | 32448a08743938 |
12 | 10566085180615 |
13 | 49cc95364c6b8 |
14 | 1d61b31b48545 |
15 | cca3bbd42e38 |
hex | 650e0c682771 |
111111012099953 has 2 divisors, whose sum is σ = 111111012099954. Its totient is φ = 111111012099952.
The previous prime is 111111012099911. The next prime is 111111012100013. The reversal of 111111012099953 is 359990210111111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 65102031627889 + 46008980472064 = 8068583^2 + 6782992^2 .
It is an emirp because it is prime and its reverse (359990210111111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 111111012099953 - 212 = 111111012095857 is a prime.
It is not a weakly prime, because it can be changed into another prime (111111012099053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55555506049976 + 55555506049977.
It is an arithmetic number, because the mean of its divisors is an integer number (55555506049977).
Almost surely, 2111111012099953 is an apocalyptic number.
It is an amenable number.
111111012099953 is a deficient number, since it is larger than the sum of its proper divisors (1).
111111012099953 is an equidigital number, since it uses as much as digits as its factorization.
111111012099953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21870, while the sum is 44.
The spelling of 111111012099953 in words is "one hundred eleven trillion, one hundred eleven billion, twelve million, ninety-nine thousand, nine hundred fifty-three".
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