Base | Representation |
---|---|
bin | 11001010000111001000111… |
… | …100011010111111111000110 |
3 | 112120102012111122000102011121 |
4 | 121100321013203113333012 |
5 | 104030424341111400032 |
6 | 1032152052233224154 |
7 | 32255402023140151 |
oct | 3120710743277706 |
9 | 476365448012147 |
10 | 111112004403142 |
11 | 3244937788aa16 |
12 | 1056630156205a |
13 | 49cca810c3452 |
14 | 1d61bc7850c98 |
15 | cca429003a97 |
hex | 650e478d7fc6 |
111112004403142 has 16 divisors (see below), whose sum is σ = 167138752043520. Its totient is φ = 55399099072968.
The previous prime is 111112004403089. The next prime is 111112004403161. The reversal of 111112004403142 is 241304400211111.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15581203 + ... + 21563809.
It is an arithmetic number, because the mean of its divisors is an integer number (10446172002720).
Almost surely, 2111112004403142 is an apocalyptic number.
111112004403142 is a deficient number, since it is larger than the sum of its proper divisors (56026747640378).
111112004403142 is a wasteful number, since it uses less digits than its factorization.
111112004403142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6008835.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 111112004403142 its reverse (241304400211111), we get a palindrome (352416404614253).
The spelling of 111112004403142 in words is "one hundred eleven trillion, one hundred twelve billion, four million, four hundred three thousand, one hundred forty-two".
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