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11111203113 = 33703734371
BaseRepresentation
bin10100101100100011…
…11000000100101001
31001200100200121020020
422112101320010221
5140223431444423
65034315351053
7542226445113
oct122621700451
931610617206
1011111203113
114791a9139a
1221a1152489
131080c914ca
1477597a3b3
154507084e3
hex296478129

11111203113 has 4 divisors (see below), whose sum is σ = 14814937488. Its totient is φ = 7407468740.

The previous prime is 11111203099. The next prime is 11111203121. The reversal of 11111203113 is 31130211111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11111203113 - 28 = 11111202857 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11111203092 and 11111203101.

It is not an unprimeable number, because it can be changed into a prime (11111203133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1851867183 + ... + 1851867188.

It is an arithmetic number, because the mean of its divisors is an integer number (3703734372).

Almost surely, 211111203113 is an apocalyptic number.

It is an amenable number.

11111203113 is a deficient number, since it is larger than the sum of its proper divisors (3703734375).

11111203113 is an equidigital number, since it uses as much as digits as its factorization.

11111203113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3703734374.

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 11111203113 its reverse (31130211111), we get a palindrome (42241414224).

The spelling of 11111203113 in words is "eleven billion, one hundred eleven million, two hundred three thousand, one hundred thirteen".

Divisors: 1 3 3703734371 11111203113