Base | Representation |
---|---|
bin | 11001010000111001001001… |
… | …010000110110010001111011 |
3 | 112120102012120122000102010101 |
4 | 121100321021100312101323 |
5 | 104030424420433212143 |
6 | 1032152055140300231 |
7 | 32255402522103151 |
oct | 3120711120662173 |
9 | 476365518012111 |
10 | 111112033100923 |
11 | 32449392000a98 |
12 | 1056630b0a1677 |
13 | 49cca8703079a |
14 | 1d61bcb5a13d1 |
15 | cca42b7c1b4d |
hex | 650e4943647b |
111112033100923 has 2 divisors, whose sum is σ = 111112033100924. Its totient is φ = 111112033100922.
The previous prime is 111112033100867. The next prime is 111112033100933. The reversal of 111112033100923 is 329001330211111.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-111112033100923 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 111112033100891 and 111112033100900.
It is not a weakly prime, because it can be changed into another prime (111112033100933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55556016550461 + 55556016550462.
It is an arithmetic number, because the mean of its divisors is an integer number (55556016550462).
Almost surely, 2111112033100923 is an apocalyptic number.
111112033100923 is a deficient number, since it is larger than the sum of its proper divisors (1).
111112033100923 is an equidigital number, since it uses as much as digits as its factorization.
111112033100923 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 28.
The spelling of 111112033100923 in words is "one hundred eleven trillion, one hundred twelve billion, thirty-three million, one hundred thousand, nine hundred twenty-three".
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