Base | Representation |
---|---|
bin | 10000001010110100001… |
… | …010000111101101101001 |
3 | 10221020000011001022202101 |
4 | 100022310022013231221 |
5 | 121201040233124111 |
6 | 2210235433533401 |
7 | 143163456065416 |
oct | 20126412075551 |
9 | 3836004038671 |
10 | 1111124114281 |
11 | 399252660775 |
12 | 15b415274261 |
13 | 80a1763a40c |
14 | 3bac8a4510d |
15 | 1dd823a9bc1 |
hex | 102b4287b69 |
1111124114281 has 2 divisors, whose sum is σ = 1111124114282. Its totient is φ = 1111124114280.
The previous prime is 1111124114263. The next prime is 1111124114351. The reversal of 1111124114281 is 1824114211111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1109895962256 + 1228152025 = 1053516^2 + 35045^2 .
It is a cyclic number.
It is not a de Polignac number, because 1111124114281 - 233 = 1102534179689 is a prime.
It is a super-2 number, since 2×11111241142812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1111124114251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555562057140 + 555562057141.
It is an arithmetic number, because the mean of its divisors is an integer number (555562057141).
Almost surely, 21111124114281 is an apocalyptic number.
It is an amenable number.
1111124114281 is a deficient number, since it is larger than the sum of its proper divisors (1).
1111124114281 is an equidigital number, since it uses as much as digits as its factorization.
1111124114281 is an evil number, because the sum of its binary digits is even.
The product of its digits is 512, while the sum is 28.
Adding to 1111124114281 its reverse (1824114211111), we get a palindrome (2935238325392).
The spelling of 1111124114281 in words is "one trillion, one hundred eleven billion, one hundred twenty-four million, one hundred fourteen thousand, two hundred eighty-one".
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