Base | Representation |
---|---|
bin | 10100101100100100… |
… | …10000110011110001 |
3 | 1001200100212202012211 |
4 | 22112102100303301 |
5 | 140223443220213 |
6 | 5034321452121 |
7 | 542230346365 |
oct | 122622206361 |
9 | 31610782184 |
10 | 11111304433 |
11 | 4792050529 |
12 | 21a11a1041 |
13 | 1080cc8668 |
14 | 7759a52a5 |
15 | 45072853d |
hex | 296490cf1 |
11111304433 has 2 divisors, whose sum is σ = 11111304434. Its totient is φ = 11111304432.
The previous prime is 11111304403. The next prime is 11111304461. The reversal of 11111304433 is 33440311111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8007923169 + 3103381264 = 89487^2 + 55708^2 .
It is an emirp because it is prime and its reverse (33440311111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11111304433 - 25 = 11111304401 is a prime.
It is a super-2 number, since 2×111113044332 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11111304403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555652216 + 5555652217.
It is an arithmetic number, because the mean of its divisors is an integer number (5555652217).
Almost surely, 211111304433 is an apocalyptic number.
It is an amenable number.
11111304433 is a deficient number, since it is larger than the sum of its proper divisors (1).
11111304433 is an equidigital number, since it uses as much as digits as its factorization.
11111304433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 11111304433 its reverse (33440311111), we get a palindrome (44551615544).
The spelling of 11111304433 in words is "eleven billion, one hundred eleven million, three hundred four thousand, four hundred thirty-three".
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