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111113113003 = 283392625841
BaseRepresentation
bin110011101111011011…
…0111000110110101011
3101121210122220222100121
41213132312320312223
53310024424104003
6123013351344111
711012325606604
oct1473666706653
9347718828317
10111113113003
1143139501412
121964b682037
13a629cbc359
145540d76dab
152d54bbdcbd
hex19dedb8dab

111113113003 has 4 divisors (see below), whose sum is σ = 111505739128. Its totient is φ = 110720486880.

The previous prime is 111113112997. The next prime is 111113113019. The reversal of 111113113003 is 300311311111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-111113113003 is a prime.

It is a super-2 number, since 2×1111131130032 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (111113113073) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 196312638 + ... + 196313203.

It is an arithmetic number, because the mean of its divisors is an integer number (27876434782).

Almost surely, 2111113113003 is an apocalyptic number.

111113113003 is a deficient number, since it is larger than the sum of its proper divisors (392626125).

111113113003 is an equidigital number, since it uses as much as digits as its factorization.

111113113003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 392626124.

The product of its (nonzero) digits is 27, while the sum is 16.

Adding to 111113113003 its reverse (300311311111), we get a palindrome (411424424114).

The spelling of 111113113003 in words is "one hundred eleven billion, one hundred thirteen million, one hundred thirteen thousand, three".

Divisors: 1 283 392625841 111113113003