1111131421401 has 4 divisors (see below), whose sum is σ = 1481508561872. Its totient is φ = 740754280932.

The previous prime is 1111131421381. The next prime is 1111131421403. The reversal of 1111131421401 is 1041241311111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1111131421401 - 2⁵ = 1111131421369 is a prime.

It is a super-2 number, since 2×1111131421401² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1111131421403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 185188570231 + ... + 185188570236.

It is an arithmetic number, because the mean of its divisors is an integer number (370377140468).

Almost surely, 2^{1111131421401} is an apocalyptic number.

It is an amenable number.

1111131421401 is a deficient number, since it is larger than the sum of its proper divisors (370377140471).

1111131421401 is an equidigital number, since it uses as much as digits as its factorization.

1111131421401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 370377140470.

The product of its (nonzero) digits is 96, while the sum is 21.

Adding to 1111131421401 its reverse (1041241311111), we get a palindrome (2152372732512).

The spelling of 1111131421401 in words is "one trillion, one hundred eleven billion, one hundred thirty-one million, four hundred twenty-one thousand, four hundred one".