Base | Representation |
---|---|
bin | 10000001010110100101… |
… | …100001000011011110011 |
3 | 10221020000202211022000001 |
4 | 100022310230020123303 |
5 | 121201100023431011 |
6 | 2210240353010431 |
7 | 143163624631225 |
oct | 20126454103363 |
9 | 3836022738001 |
10 | 1111133030131 |
11 | 3992576a0343 |
12 | 15b418253a17 |
13 | 80a1943c677 |
14 | 3bac9cc6415 |
15 | 1dd8306b7c1 |
hex | 102b4b086f3 |
1111133030131 has 2 divisors, whose sum is σ = 1111133030132. Its totient is φ = 1111133030130.
The previous prime is 1111133030107. The next prime is 1111133030171. The reversal of 1111133030131 is 1310303311111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1111133030131 - 29 = 1111133029619 is a prime.
It is a super-2 number, since 2×11111330301312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1111133030099 and 1111133030108.
It is not a weakly prime, because it can be changed into another prime (1111133030171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555566515065 + 555566515066.
It is an arithmetic number, because the mean of its divisors is an integer number (555566515066).
Almost surely, 21111133030131 is an apocalyptic number.
1111133030131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1111133030131 is an equidigital number, since it uses as much as digits as its factorization.
1111133030131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81, while the sum is 19.
Adding to 1111133030131 its reverse (1310303311111), we get a palindrome (2421436341242).
The spelling of 1111133030131 in words is "one trillion, one hundred eleven billion, one hundred thirty-three million, thirty thousand, one hundred thirty-one".
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