Base | Representation |
---|---|
bin | 1010000110110001010110… |
… | …1011111011011110110001 |
3 | 1110100020120122122020200202 |
4 | 2201230111223323132301 |
5 | 2424022214210411423 |
6 | 35344305500124545 |
7 | 2224526642422121 |
oct | 241542553733661 |
9 | 43306518566622 |
10 | 11111444232113 |
11 | 35a4378659a85 |
12 | 12b5580236755 |
13 | 627a5cbb8674 |
14 | 2a5b224a2c81 |
15 | 14407a482728 |
hex | a1b15afb7b1 |
11111444232113 has 2 divisors, whose sum is σ = 11111444232114. Its totient is φ = 11111444232112.
The previous prime is 11111444232073. The next prime is 11111444232151. The reversal of 11111444232113 is 31123244411111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10947283934224 + 164160297889 = 3308668^2 + 405167^2 .
It is a cyclic number.
It is not a de Polignac number, because 11111444232113 - 210 = 11111444231089 is a prime.
It is not a weakly prime, because it can be changed into another prime (11111444232313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5555722116056 + 5555722116057.
It is an arithmetic number, because the mean of its divisors is an integer number (5555722116057).
Almost surely, 211111444232113 is an apocalyptic number.
It is an amenable number.
11111444232113 is a deficient number, since it is larger than the sum of its proper divisors (1).
11111444232113 is an equidigital number, since it uses as much as digits as its factorization.
11111444232113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2304, while the sum is 29.
Adding to 11111444232113 its reverse (31123244411111), we get a palindrome (42234688643224).
The spelling of 11111444232113 in words is "eleven trillion, one hundred eleven billion, four hundred forty-four million, two hundred thirty-two thousand, one hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.147 sec. • engine limits •