Base | Representation |
---|---|
bin | 10100101100101001… |
… | …11101010101001011 |
3 | 1001200102012122120001 |
4 | 22112110331111023 |
5 | 140224133323313 |
6 | 5034344543431 |
7 | 542236351525 |
oct | 122624752513 |
9 | 31612178501 |
10 | 11112011083 |
11 | 4792493438 |
12 | 21a1481b77 |
13 | 10811b51b4 |
14 | 775b0aa15 |
15 | 450817add |
hex | 29653d54b |
11112011083 has 2 divisors, whose sum is σ = 11112011084. Its totient is φ = 11112011082.
The previous prime is 11112011041. The next prime is 11112011093. The reversal of 11112011083 is 38011021111.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11112011083 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11112011083.
It is not a weakly prime, because it can be changed into another prime (11112011093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5556005541 + 5556005542.
It is an arithmetic number, because the mean of its divisors is an integer number (5556005542).
Almost surely, 211112011083 is an apocalyptic number.
11112011083 is a deficient number, since it is larger than the sum of its proper divisors (1).
11112011083 is an equidigital number, since it uses as much as digits as its factorization.
11112011083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 19.
Adding to 11112011083 its reverse (38011021111), we get a palindrome (49123032194).
The spelling of 11112011083 in words is "eleven billion, one hundred twelve million, eleven thousand, eighty-three".
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