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111120120110257 is a prime number
BaseRepresentation
bin11001010001000000101011…
…010010010101110010110001
3112120102222110020011001101121
4121101000223102111302301
5104031043001222012012
61032155513425102241
732256110110411636
oct3121005322256261
9476388406131347
10111120120110257
11324518619a7885
12105679a7487981
134a007755b94cb
141d6235763818d
15cca751757a07
hex65102b495cb1

111120120110257 has 2 divisors, whose sum is σ = 111120120110258. Its totient is φ = 111120120110256.

The previous prime is 111120120110221. The next prime is 111120120110269. The reversal of 111120120110257 is 752011021021111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 95953955680881 + 15166164429376 = 9795609^2 + 3894376^2 .

It is an emirp because it is prime and its reverse (752011021021111) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-111120120110257 is a prime.

It is not a weakly prime, because it can be changed into another prime (111120120110287) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55560060055128 + 55560060055129.

It is an arithmetic number, because the mean of its divisors is an integer number (55560060055129).

Almost surely, 2111120120110257 is an apocalyptic number.

It is an amenable number.

111120120110257 is a deficient number, since it is larger than the sum of its proper divisors (1).

111120120110257 is an equidigital number, since it uses as much as digits as its factorization.

111120120110257 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 280, while the sum is 25.

Adding to 111120120110257 its reverse (752011021021111), we get a palindrome (863131141131368).

The spelling of 111120120110257 in words is "one hundred eleven trillion, one hundred twenty billion, one hundred twenty million, one hundred ten thousand, two hundred fifty-seven".