Base | Representation |
---|---|
bin | 10000001010111000110… |
… | …011010001101101100011 |
3 | 10221020012120121221100012 |
4 | 100022320303101231203 |
5 | 121201220203341003 |
6 | 2210251255315135 |
7 | 143165423154446 |
oct | 20127063215543 |
9 | 3836176557305 |
10 | 1111202012003 |
11 | 399292626456 |
12 | 15b43737baab |
13 | 80a2a812945 |
14 | 3bad512165d |
15 | 1dd891458d8 |
hex | 102b8cd1b63 |
1111202012003 has 2 divisors, whose sum is σ = 1111202012004. Its totient is φ = 1111202012002.
The previous prime is 1111202011979. The next prime is 1111202012023. The reversal of 1111202012003 is 3002102021111.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1111202012003 - 212 = 1111202007907 is a prime.
It is a super-2 number, since 2×11112020120032 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1111202012023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555601006001 + 555601006002.
It is an arithmetic number, because the mean of its divisors is an integer number (555601006002).
Almost surely, 21111202012003 is an apocalyptic number.
1111202012003 is a deficient number, since it is larger than the sum of its proper divisors (1).
1111202012003 is an equidigital number, since it uses as much as digits as its factorization.
1111202012003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 1111202012003 its reverse (3002102021111), we get a palindrome (4113304033114).
The spelling of 1111202012003 in words is "one trillion, one hundred eleven billion, two hundred two million, twelve thousand, three".
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