Base | Representation |
---|---|
bin | 11001010001000000110111… |
… | …100000110001011010011001 |
3 | 112120102222222112002201001111 |
4 | 121101000313200301122121 |
5 | 104031043411224014433 |
6 | 1032155550033220321 |
7 | 32256115151000335 |
oct | 3121006740613231 |
9 | 476388875081044 |
10 | 111120325219993 |
11 | 3245195775a861 |
12 | 10567a441016a1 |
13 | 4a007a8c4250b |
14 | 1d6237698a7c5 |
15 | cca764770dcd |
hex | 651037831699 |
111120325219993 has 2 divisors, whose sum is σ = 111120325219994. Its totient is φ = 111120325219992.
The previous prime is 111120325219979. The next prime is 111120325220041. The reversal of 111120325219993 is 399912523021111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 100621221806169 + 10499103413824 = 10031013^2 + 3240232^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-111120325219993 is a prime.
It is not a weakly prime, because it can be changed into another prime (111120395219993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55560162609996 + 55560162609997.
It is an arithmetic number, because the mean of its divisors is an integer number (55560162609997).
Almost surely, 2111120325219993 is an apocalyptic number.
It is an amenable number.
111120325219993 is a deficient number, since it is larger than the sum of its proper divisors (1).
111120325219993 is an equidigital number, since it uses as much as digits as its factorization.
111120325219993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 262440, while the sum is 49.
The spelling of 111120325219993 in words is "one hundred eleven trillion, one hundred twenty billion, three hundred twenty-five million, two hundred nineteen thousand, nine hundred ninety-three".
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