Search a number
-
+
11112100021993 is a prime number
BaseRepresentation
bin1010000110110011110011…
…0001100100011011101001
31110100022021100121211021211
42201230330301210123221
52424030040101200433
635344454524033121
72224552124512015
oct241547461443351
943308240554254
1011112100021993
1135a4684852693
1212b57239927a1
13627b35a18b09
142a5b8560d545
151440b7d208cd
hexa1b3cc646e9

11112100021993 has 2 divisors, whose sum is σ = 11112100021994. Its totient is φ = 11112100021992.

The previous prime is 11112100021969. The next prime is 11112100022027. The reversal of 11112100021993 is 39912000121111.

11112100021993 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6186576722089 + 4925523299904 = 2487283^2 + 2219352^2 .

It is an emirp because it is prime and its reverse (39912000121111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11112100021993 - 29 = 11112100021481 is a prime.

It is not a weakly prime, because it can be changed into another prime (11112100021093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5556050010996 + 5556050010997.

It is an arithmetic number, because the mean of its divisors is an integer number (5556050010997).

Almost surely, 211112100021993 is an apocalyptic number.

It is an amenable number.

11112100021993 is a deficient number, since it is larger than the sum of its proper divisors (1).

11112100021993 is an equidigital number, since it uses as much as digits as its factorization.

11112100021993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 31.

The spelling of 11112100021993 in words is "eleven trillion, one hundred twelve billion, one hundred million, twenty-one thousand, nine hundred ninety-three".