Base | Representation |
---|---|
bin | 10100101100101010… |
… | …10011101000100001 |
3 | 1001200102101021212101 |
4 | 22112111103220201 |
5 | 140224144234213 |
6 | 5034350530401 |
7 | 542240212045 |
oct | 122625235041 |
9 | 31612337771 |
10 | 11112102433 |
11 | 4792546033 |
12 | 21a1506a01 |
13 | 1081217953 |
14 | 775b32025 |
15 | 450834bdd |
hex | 296553a21 |
11112102433 has 2 divisors, whose sum is σ = 11112102434. Its totient is φ = 11112102432.
The previous prime is 11112102409. The next prime is 11112102451. The reversal of 11112102433 is 33420121111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9893883024 + 1218219409 = 99468^2 + 34903^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11112102433 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11112102433.
It is not a weakly prime, because it can be changed into another prime (11112102473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5556051216 + 5556051217.
It is an arithmetic number, because the mean of its divisors is an integer number (5556051217).
Almost surely, 211112102433 is an apocalyptic number.
It is an amenable number.
11112102433 is a deficient number, since it is larger than the sum of its proper divisors (1).
11112102433 is an equidigital number, since it uses as much as digits as its factorization.
11112102433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 11112102433 its reverse (33420121111), we get a palindrome (44532223544).
The spelling of 11112102433 in words is "eleven billion, one hundred twelve million, one hundred two thousand, four hundred thirty-three".
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