111121202220043 has 2 divisors, whose sum is σ = 111121202220044. Its totient is φ = 111121202220042.

The previous prime is 111121202220001. The next prime is 111121202220079. The reversal of 111121202220043 is 340022202121111.

It is a strong prime.

It is an emirp because it is prime and its reverse (340022202121111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111121202220043 - 2²⁹ = 111120665349131 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 111121202219996 and 111121202220023.

It is not a weakly prime, because it can be changed into another prime (111121202220443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55560601110021 + 55560601110022.

It is an arithmetic number, because the mean of its divisors is an integer number (55560601110022).

Almost surely, 2^{111121202220043} is an apocalyptic number.

111121202220043 is a deficient number, since it is larger than the sum of its proper divisors (1).

111121202220043 is an equidigital number, since it uses as much as digits as its factorization.

111121202220043 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 111121202220043 its reverse (340022202121111), we get a palindrome (451143404341154).

The spelling of 111121202220043 in words is "one hundred eleven trillion, one hundred twenty-one billion, two hundred two million, two hundred twenty thousand, forty-three".