Base | Representation |
---|---|
bin | 10100101100101010… |
… | …11010111100110011 |
3 | 1001200102102210222101 |
4 | 22112111122330303 |
5 | 140224201214103 |
6 | 5034351321231 |
7 | 542240365321 |
oct | 122625327463 |
9 | 31612383871 |
10 | 11112132403 |
11 | 47925665a9 |
12 | 21a1520217 |
13 | 1081228498 |
14 | 775b3cd11 |
15 | 45083da1d |
hex | 29655af33 |
11112132403 has 4 divisors (see below), whose sum is σ = 11348560800. Its totient is φ = 10875704008.
The previous prime is 11112132359. The next prime is 11112132487. The reversal of 11112132403 is 30423121111.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30423121111 = 37573 ⋅809707.
It is a cyclic number.
It is not a de Polignac number, because 11112132403 - 213 = 11112124211 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11112132103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 118214128 + ... + 118214221.
It is an arithmetic number, because the mean of its divisors is an integer number (2837140200).
Almost surely, 211112132403 is an apocalyptic number.
11112132403 is a deficient number, since it is larger than the sum of its proper divisors (236428397).
11112132403 is an equidigital number, since it uses as much as digits as its factorization.
11112132403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 236428396.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 11112132403 its reverse (30423121111), we get a palindrome (41535253514).
The spelling of 11112132403 in words is "eleven billion, one hundred twelve million, one hundred thirty-two thousand, four hundred three".
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