Base | Representation |
---|---|
bin | 1010000110110111001111… |
… | …0111001100111000111011 |
3 | 1110100101122202201020022221 |
4 | 2201231303313030320323 |
5 | 2424033433201322212 |
6 | 35345130341224511 |
7 | 2224614046336435 |
oct | 241556367147073 |
9 | 43311582636287 |
10 | 11113024245307 |
11 | 35a500951a306 |
12 | 12b5941402137 |
13 | 627c5234400a |
14 | 2a5c32273655 |
15 | 14411e034807 |
hex | a1b73dcce3b |
11113024245307 has 2 divisors, whose sum is σ = 11113024245308. Its totient is φ = 11113024245306.
The previous prime is 11113024245293. The next prime is 11113024245329. The reversal of 11113024245307 is 70354242031111.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11113024245307 is a prime.
It is not a weakly prime, because it can be changed into another prime (11113021245307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5556512122653 + 5556512122654.
It is an arithmetic number, because the mean of its divisors is an integer number (5556512122654).
Almost surely, 211113024245307 is an apocalyptic number.
11113024245307 is a deficient number, since it is larger than the sum of its proper divisors (1).
11113024245307 is an equidigital number, since it uses as much as digits as its factorization.
11113024245307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20160, while the sum is 34.
Adding to 11113024245307 its reverse (70354242031111), we get a palindrome (81467266276418).
The spelling of 11113024245307 in words is "eleven trillion, one hundred thirteen billion, twenty-four million, two hundred forty-five thousand, three hundred seven".
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