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111130311323 = 472364474709
BaseRepresentation
bin110011101111111100…
…0011111101010011011
3101121211212021202000102
41213133320133222123
53310043324430243
6123015204130015
711012625026513
oct1473770375233
9347755252012
10111130311323
11431481887a9
121965539690b
13a630731485
145543372843
152d564699b8
hex19dfe1fa9b

111130311323 has 4 divisors (see below), whose sum is σ = 113494786080. Its totient is φ = 108765836568.

The previous prime is 111130311319. The next prime is 111130311337. The reversal of 111130311323 is 323113031111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 111130311323 - 22 = 111130311319 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 111130311295 and 111130311304.

It is not an unprimeable number, because it can be changed into a prime (111130311923) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1182237308 + ... + 1182237401.

It is an arithmetic number, because the mean of its divisors is an integer number (28373696520).

Almost surely, 2111130311323 is an apocalyptic number.

111130311323 is a deficient number, since it is larger than the sum of its proper divisors (2364474757).

111130311323 is an equidigital number, since it uses as much as digits as its factorization.

111130311323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2364474756.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 111130311323 its reverse (323113031111), we get a palindrome (434243342434).

The spelling of 111130311323 in words is "one hundred eleven billion, one hundred thirty million, three hundred eleven thousand, three hundred twenty-three".

Divisors: 1 47 2364474709 111130311323