Base | Representation |
---|---|
bin | 11001010001001010110101… |
… | …000110001011100100100001 |
3 | 112120111000121000012011202002 |
4 | 121101022311012023210201 |
5 | 104031232313130104212 |
6 | 1032204515312533345 |
7 | 32256644220043442 |
oct | 3121126506134441 |
9 | 476430530164662 |
10 | 111131022113057 |
11 | 32456446891951 |
12 | 10569b2a551255 |
13 | 4a017c2121b3b |
14 | 1d62aad4b92c9 |
15 | ccab8d8daac2 |
hex | 6512b518b921 |
111131022113057 has 2 divisors, whose sum is σ = 111131022113058. Its totient is φ = 111131022113056.
The previous prime is 111131022112951. The next prime is 111131022113081. The reversal of 111131022113057 is 750311220131111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 69260494199521 + 41870527913536 = 8322289^2 + 6470744^2 .
It is a cyclic number.
It is not a de Polignac number, because 111131022113057 - 214 = 111131022096673 is a prime.
It is not a weakly prime, because it can be changed into another prime (111131022110057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55565511056528 + 55565511056529.
It is an arithmetic number, because the mean of its divisors is an integer number (55565511056529).
Almost surely, 2111131022113057 is an apocalyptic number.
It is an amenable number.
111131022113057 is a deficient number, since it is larger than the sum of its proper divisors (1).
111131022113057 is an equidigital number, since it uses as much as digits as its factorization.
111131022113057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1260, while the sum is 29.
Adding to 111131022113057 its reverse (750311220131111), we get a palindrome (861442242244168).
The spelling of 111131022113057 in words is "one hundred eleven trillion, one hundred thirty-one billion, twenty-two million, one hundred thirteen thousand, fifty-seven".
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