Base | Representation |
---|---|
bin | 10000001010111111010… |
… | …000000110001010011011 |
3 | 10221020111010020222202111 |
4 | 100022333100012022123 |
5 | 121201430404331141 |
6 | 2210310123013151 |
7 | 143201206045351 |
oct | 20127720061233 |
9 | 3836433228674 |
10 | 1111310230171 |
11 | 399338720359 |
12 | 15b46766a1b7 |
13 | 80a47072c6b |
14 | 3bb056517d1 |
15 | 1dd938c0381 |
hex | 102bf40629b |
1111310230171 has 2 divisors, whose sum is σ = 1111310230172. Its totient is φ = 1111310230170.
The previous prime is 1111310230159. The next prime is 1111310230243. The reversal of 1111310230171 is 1710320131111.
It is a weak prime.
It is an emirp because it is prime and its reverse (1710320131111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1111310230171 - 211 = 1111310228123 is a prime.
It is a super-4 number, since 4×11113102301714 (a number of 49 digits) contains 4444 as substring.
It is not a weakly prime, because it can be changed into another prime (1111310230271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555655115085 + 555655115086.
It is an arithmetic number, because the mean of its divisors is an integer number (555655115086).
Almost surely, 21111310230171 is an apocalyptic number.
1111310230171 is a deficient number, since it is larger than the sum of its proper divisors (1).
1111310230171 is an equidigital number, since it uses as much as digits as its factorization.
1111310230171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 126, while the sum is 22.
Adding to 1111310230171 its reverse (1710320131111), we get a palindrome (2821630361282).
The spelling of 1111310230171 in words is "one trillion, one hundred eleven billion, three hundred ten million, two hundred thirty thousand, one hundred seventy-one".
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