Base | Representation |
---|---|
bin | 10000001010111111010… |
… | …110110110101111110001 |
3 | 10221020111020121000022000 |
4 | 100022333112312233301 |
5 | 121201431333031113 |
6 | 2210310225004213 |
7 | 143201230105212 |
oct | 20127726665761 |
9 | 3836436530260 |
10 | 1111312002033 |
11 | 399339720602 |
12 | 15b468183669 |
13 | 80a475435bc |
14 | 3bb05993409 |
15 | 1dd93b20373 |
hex | 102bf5b6bf1 |
1111312002033 has 32 divisors (see below), whose sum is σ = 1671218265600. Its totient is φ = 729704522448.
The previous prime is 1111312002023. The next prime is 1111312002061. The reversal of 1111312002033 is 3302002131111.
It is not a de Polignac number, because 1111312002033 - 214 = 1111311985649 is a prime.
It is a super-2 number, since 2×11113120020332 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1111312001997 and 1111312002015.
It is not an unprimeable number, because it can be changed into a prime (1111312002023) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 12653610 + ... + 12741132.
It is an arithmetic number, because the mean of its divisors is an integer number (52225570800).
Almost surely, 21111312002033 is an apocalyptic number.
It is an amenable number.
1111312002033 is a deficient number, since it is larger than the sum of its proper divisors (559906263567).
1111312002033 is an equidigital number, since it uses as much as digits as its factorization.
1111312002033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 94618 (or 94612 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 18.
Adding to 1111312002033 its reverse (3302002131111), we get a palindrome (4413314133144).
The spelling of 1111312002033 in words is "one trillion, one hundred eleven billion, three hundred twelve million, two thousand, thirty-three".
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