Base | Representation |
---|---|
bin | 10000001010111111011… |
… | …011011101111011110001 |
3 | 10221020111022212102212001 |
4 | 100022333123131323301 |
5 | 121201432140223441 |
6 | 2210310310534001 |
7 | 143201243302231 |
oct | 20127733357361 |
9 | 3836438772761 |
10 | 1111313211121 |
11 | 39933a376a53 |
12 | 15b468667301 |
13 | 80a47877a39 |
14 | 3bb05bc9cc1 |
15 | 1dd93cad731 |
hex | 102bf6ddef1 |
1111313211121 has 2 divisors, whose sum is σ = 1111313211122. Its totient is φ = 1111313211120.
The previous prime is 1111313211097. The next prime is 1111313211157. The reversal of 1111313211121 is 1211123131111.
It is a m-pointer prime, because the next prime (1111313211157) can be obtained adding 1111313211121 to its product of digits (36).
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1104466476096 + 6846735025 = 1050936^2 + 82745^2 .
It is a cyclic number.
It is not a de Polignac number, because 1111313211121 - 217 = 1111313080049 is a prime.
It is not a weakly prime, because it can be changed into another prime (1111313271121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555656605560 + 555656605561.
It is an arithmetic number, because the mean of its divisors is an integer number (555656605561).
Almost surely, 21111313211121 is an apocalyptic number.
It is an amenable number.
1111313211121 is a deficient number, since it is larger than the sum of its proper divisors (1).
1111313211121 is an equidigital number, since it uses as much as digits as its factorization.
1111313211121 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 36, while the sum is 19.
Adding to 1111313211121 its reverse (1211123131111), we get a palindrome (2322436342232).
The spelling of 1111313211121 in words is "one trillion, one hundred eleven billion, three hundred thirteen million, two hundred eleven thousand, one hundred twenty-one".
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