1111313320121 has 2 divisors, whose sum is σ = 1111313320122. Its totient is φ = 1111313320120.

The previous prime is 1111313320049. The next prime is 1111313320129. The reversal of 1111313320121 is 1210233131111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 745699604521 + 365613715600 = 863539^2 + 604660^2 .

It is a cyclic number.

It is not a de Polignac number, because 1111313320121 - 2¹⁰ = 1111313319097 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1111313320093 and 1111313320102.

It is not a weakly prime, because it can be changed into another prime (1111313320129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555656660060 + 555656660061.

It is an arithmetic number, because the mean of its divisors is an integer number (555656660061).

Almost surely, 2^{1111313320121} is an apocalyptic number.

It is an amenable number.

1111313320121 is a deficient number, since it is larger than the sum of its proper divisors (1).

1111313320121 is an equidigital number, since it uses as much as digits as its factorization.

1111313320121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 20.

Adding to 1111313320121 its reverse (1210233131111), we get a palindrome (2321546451232).

The spelling of 1111313320121 in words is "one trillion, one hundred eleven billion, three hundred thirteen million, three hundred twenty thousand, one hundred twenty-one".