111131340114042 has 48 divisors (see below), whose sum is σ = 248182636553280. Its totient is φ = 35918192390976.

The previous prime is 111131340114023. The next prime is 111131340114083. The reversal of 111131340114042 is 240411043131111.

111131340114042 is a `hidden beast` number, since 1 + 1 + 113 + 1 + 3 + 401 + 140 + 4 + 2 = 666.

It is a junction number, because it is equal to n+sod(n) for n = 111131340113997 and 111131340114015.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 523910542 + ... + 524122617.

It is an arithmetic number, because the mean of its divisors is an integer number (5170471594860).

Almost surely, 2^{111131340114042} is an apocalyptic number.

111131340114042 is an abundant number, since it is smaller than the sum of its proper divisors (137051296439238).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

111131340114042 is a wasteful number, since it uses less digits than its factorization.

111131340114042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1048033347 (or 1048033344 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 27.

Adding to 111131340114042 its reverse (240411043131111), we get a palindrome (351542383245153).

The spelling of 111131340114042 in words is "one hundred eleven trillion, one hundred thirty-one billion, three hundred forty million, one hundred fourteen thousand, forty-two".